描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011

样例输出

3
0
3

来源

网络

上传者

naonao

代码

#include <stdio.h>
int	main(){
	int n,i,j=0,k=0,l=0;
	scanf("%d",&n);
	getchar();
	char a[10];
	char b[1000];
 	for(i=0;i<n;i++){
		scanf("%s",a);
		getchar();
		scanf("%s",b);
		getchar();
		while(b[j]!='\0'){
			while(a[k]!='\0'){
				if(a[k]!=b[j+k]){
				break;
				}
				k++;
				if(a[k]=='\0'){
					l++;
					break;
				}
			}
			j++;
			k=0;	
		} 
		printf("%d\n",l);
		k=0;
		j=0;
		l=0;
 	}	
}